A jogger travels a route that has two parts. The first is a displacement A of 2.

Question

A jogger travels a route that has two parts. The first is a displacement A of 2.60 km due south, and the second involves a displacement B that points due east. The resultant displacement A + B has a magnitude of 4.35 km. (a) What is the magnitude of B, and (b) what is the direction of A + B as a positive angle relative to due south? Suppose that A - B had a magnitude of 4.35 km. (c) What then would be the magnitude of B, and (d) what is the direction of A - B relative to due south? (a) Number Units (b) Number Units (c) Number Units (d) Number Units

Explanation / Answer

a)

as resultant is 4.35 and down south is 2.6
east is perpendicular to south therefore displacement towards east is sqrt of (4.35^2-2.6^2) according to pythagoras theorem

B= 3.48 due east

b)The angle can be found through any of the reverse trig functions

x = arctan(3.48/2.6)

= 53.23 degrees east of south

c)

suppose a-b = 4.35 then b wud be northwards
d)magnitude of b wud be 6.95 towards the north

considering south positive

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.