A wood block weighs 100 N. (a) What is the normal force exerted by the table? (b

Question

A wood block weighs 100 N. (a) What is the normal force exerted by the table? (b) What is the force of (static) friction? (2) The table top is tilled to a 10degree angle. but the block remains at rest: (a) what is the normal force exerted by the table? (b) what is the force of (static) friction? (3) The table top is tilted to a 30degree angle, and the block still doesn't move: (a) What is the normal force excreted by the table? (b) What is force of (static) friction? (4) Finally, when the table top is tilted to a 40degree angle, the block slides with a 2 m/s^2 acceleration: (a) What is the normal force exerted by the table? (b) What is the force of (kinetic) friction?

Explanation / Answer

1)

Normal force Fs = mg = 100 N

frictional force = 0N ( as no horizontal force is acting

2)

Normal Force = mg cos10 = 98.48 N

friction force = mgsin10 = 17.3648 N

3)

Normal Force = mgcos30 = 86.6 N

frictional Force = mgsin30 = 50 N

4)

Normal force = mg cos 40 = 76.36 N

fri tional force = mgsin40 - ma = 43.87N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.