The force table consists of a circular platform with marking at the edge showing

Question

The force table consists of a circular platform with marking at the edge showing the angle for a circle centered about the center of the table. A mass, m = 240 gram is places on a hanger which has a mass of 50 g, giving a total mass of 290 g. The hanger is hung at an angle of 120 deg over a pulley attached to the force table using a string of negligible mass. The pulley over which the string rests has very low friction force.

The tension in the string: 2.84 N.
The components: Fx = -1.42 N, Fy = 2.46 N
Total mass needed to balance the force: 290 g
Angle should the mass be hung: 300 deg.

***This is where I'm confused and having problems***

The balancing mass used in the last exercise is kept in place. The original mass that was hanging at 120 deg is removed and replaced with its components with the x and y axes at 0 deg and the 90deg respectively. What is the total mass (mass plus hanger) needed along the x-axis? Along which direction should the mass be hung?
Mass = ??
+x or -X

What is the total mass (mass plus hanger) needed along the y-axis? Along which direction should the mass be hung?
Mass = ??
+y or -y

Explanation / Answer

The horizontal component of the 290g weight (290g=0.29kg, 50g = 0.05kg)
0.29*9.8*cos120 = -1.421 N (negative means towards 180deg) = 9.8*(0.05+mx)
=> mx = 195 g ; 195 +50=245g including hanger
Hung at 0 degrees to counteract horizontal force component at 180 degrees
The vertical component of the 270g weight
0.29*9.8*sin120 = 2.46 N = 9.8*(0.05+my) => my = 201.02 g
Postive meaning towards 90 degrees
201.02+50=251.02 g including hanger
Hung at 270 degrees

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