10:04 PM 796 D + webassign.net chapter4-motion in 2D A Force F1 Of Magnitude 5.6

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10:04 PM 796 D + webassign.net chapter4-motion in 2D A Force F1 Of Magnitude 5.60 Units Acts At The.. I Chegg.com Assignment Submission For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer Assignment Scoring Your last submission is used for vour score 1. +-13 points SerPSET9 4.P.003 My Notes My Notes Ask Your Tea Ask Your Teacher Suppose the position vector for a particle is given as a function of time by r (t)-x(t)i + y(t)j, with x(t) = at + b and y(t) = ct2 + d, where a = 1.50 m/s, b = 1.35 m, c = 0.131 m/s2, and d = 1.18 m (a) Calculate the average velocity during the time interval from t-1.95 s to t-3.95 s m/s (b) Determine the velocity at t 1.95 s VE m/s Determine the speed at t = 1.95 s m/s Need Help? Read It 2. -4 points SerPSET9 4.P.007 My Notes My Notes Ask Your Tea Ask Your Teacher

Explanation / Answer

here,

x = at + b

y = ct^2 + d

vx = dx/dt = a

vy = dy/dt = 2 *c * t

a) at t = 1.95 s

x = 1.5 * 1.95 + 1.35

x = 4.275 m

y = 0.131 * 1.95^2 + 1.18

y = 2.151 m

at t = 3.95 s

x = 1.5 * 3.95 + 1.35

x = 7.275 m

y = 0.131 * 3.95^2 + 1.18

y = 3.223 m

average velocity during this time = ((7.275 - 4.275)i + (3.223 - 2.151)j)/2

average velocity during this time = 1.5 i + 0.536 j

b)

at t = 1.95 s

vx = 1.5 m/s

vy = 2 * 0.131 * 1.95

vy = 0.511 m/s

velocity at 1.95 s

is v = 1.5 i + 0.511 j m/s

c)

speed = sqrt(1.5^2 + 0.511^2) = 1.585 m/s

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