A. What are the x and y components of the net force (FNETx and FNETy) on a parti
ID: 1407495 • Letter: A
Question
A. What are the x and y components of the net force (FNETx and FNETy) on a particle with mass = 4.3 kg and acceleration components ax = 2.1 m/s2 and ay = 3 m/s2? FNETx: N FNETy: N B. If there are two individual forces on the particle (F1 and F2), what are the components of F2 (F2x and F2y) if the components of F1 are F1x = -12.4 N and F1y = 17.8 N? A. What are the x and y components of the net force (FNETx and FNETy) on a particle with mass = 4.3 kg and acceleration components ax = 2.1 m/s2 and ay = 3 m/s2? FNETx: N FNETy: N B. If there are two individual forces on the particle (F1 and F2), what are the components of F2 (F2x and F2y) if the components of F1 are F1x = -12.4 N and F1y = 17.8 N? A. What are the x and y components of the net force (FNETx and FNETy) on a particle with mass = 4.3 kg and acceleration components ax = 2.1 m/s2 and ay = 3 m/s2? FNETx: N FNETy: N B. If there are two individual forces on the particle (F1 and F2), what are the components of F2 (F2x and F2y) if the components of F1 are F1x = -12.4 N and F1y = 17.8 N?Explanation / Answer
A) Fnetx= m*ax=4.3*2.1=9.03 N
Fnety=m*ay=4.3*3=12.9N
B)Fnet= F1+F2
Fnetx=F1x+F2x =9.03 =-12.4+F2x => F2x=21.43N
Fnety=F1y+F2y =12.9 =17.8+F2x => F2x=21.43N => F2y= -4.9 N
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