A putting green islocated 190 feet horizontally and 30 feet vertically from the

Question

A putting green islocated 190 feet horizontally and 30 feet vertically from the tee. What must be the magnitude and direction of the initial velocity if a ball is to strike the green at this location after a time of 3.3 seconds?

Initial Velocity Magnitude =  [Num]feet/second

Initial Velocity Angle =  [Num]degrees

A putting green islocated 190 feet horizontally and 30 feet vertically from the tee. What must be the magnitude and direction of the initial velocity if a ball is to strike the green at this location after a time of 3.3 seconds?

Initial Velocity Magnitude =  [Num]feet/second

Initial Velocity Angle =  [Num]degrees

Explanation / Answer

given,

horizontal distance = 190 feet

vertical distance = 30 feet

time = 3.3 sec

horizontal speed = horizontal distance / time , since no force is acting

horizontal speed = 190 / 3.3

horizontal speed = 190 / 3.3

horizontal speed = 57.58 feet / s

vertical distance = vertical velocity * time - 0.5 * acceleration due to gravity *time^2

30 = vertical velocity * 3.3 - 0.5 * 32.174 * 3.3^2

vertical velocity = 62.178 feet/s

resultant velocity = sqrt(57.58^2 + 62.178^2)

Initial Velocity Magnitude = 84.744 feet / s

angle = tan^-1(62.178 / 57.58)

Initial Velocity Angle = 47.2 degree

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