A car sits in an entrance ramp to a freeway, waiting for a break in the traffic.

Question

A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. The driver sees a small gap between a van and an 18-wheel truck and accelerates with constant acceleration along the ramp and onto the freeway. The car starts from rest, moves in a straight line, and has a speed of 16.0 m/s when it reaches the end of the ramp, which has length 122 m .

Part A

What is the acceleration of the car?

Part B

How much time does it take the car to travel the length of the ramp?

Part C

The traffic on the freeway is moving at a constant speed of 16.0 m/s . What distance does the traffic travel while the car is moving the length of the ramp?

Explanation / Answer

speed , v = 16 m/s

length of ramp , L = 122 m

a) using third equation of motion

v^2 - u^2 = 2 * a * d

16^2 - 0 = 2 * a * 122

solving for a

a = 1.05 m/s^2

the accelertion of car is 1.05 m/s^2

b)

using first equation of motion

v= u + a*t

16 = 1.05 * t

t = 15.25 s

the time taken is 15.25 s

C)

distance = speed * time

distance = 16 * 15.25 m

distance = 244 m

the traffic on freeway moves 244 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.