#27) A ball is thrown horizontally from the top of 60.0m building and lands 100.
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Question
#27) A ball is thrown horizontally from the top of 60.0m building and lands 100.0m from the base of the building. Ignore air resistance
a) How long is the ball in the air?
b)What must have been the initial horizontal component of the velocity?
c) What is the vertical component of the velocity just before the ball hits te ground?
d) What is the velocity( including both the horizontal and vertical components) of the ball just before it hits the ground?
16) During a lecture demonstration, a professor places two coins on the edge of a table. She then flicks one of the coins horizontally off the table, simultaneously nudging the other over the edge. Describe the subsequent motion of the two coins, in particular discussing whether they hit the floor at the same time.
25) A projectile is lauched at ground level with an initial peed of 50.0m/s at an angle of 30.0 degree centigrade above the horizontal. It strikes a target above the ground 3.00 seconds later. what are the x and y distance from where the projectile was launched to where it lands?
46) A basket ball player is tunning at 5.00m/s directly toward the basket when he jumps into the air to dunk the ball. He maintains his horizontal velocity
a) What vertical velocity does he need to rise 0.750m abov the floor?
b) How far from the basket( measured in the horizontal direction) must he start his jump to reach his maximum height at the same time as he reaches the basket?
55) Verify that the coin dropped by the airline passenger in the example 3.8 travels 144m horizontally while falling 1.50m in the frame of reference of the earth.
( please show all workings and solutions in the above questions)
Explanation / Answer
27)
Height of building , H = 60 m
a) let the time of flight is tf
now , as there is no initial vertical velocity
H = 0.5 * g * tf^2
60 = 0.5 * 9.8 * tf^2
tf = 3.5 s
the ball is in air for 3.5 s
b)
initial horizontal velocity = 100/3.5
initial horizontal velocity =28.6 m/s
initial horizontal velocity is 28.6 m/s
c)
Using first equation of motion
vy = u + g * t
vy = 9.8 * 3.5
vy = 34.3 m/s
the vertical velocity is 34.3 m/s in downwards direction
d)
Velocity = 28.6 i m/s + 34.3 j m/s
assuming downwards as positive direction
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