A 68 µC point charge is at the origin. Find the electric field at the following

Question

A 68 µC point charge is at the origin. Find the electric field at the following points. (a) x = 45 cm, y = 0 i MN/C
(b) x = 50 cm, y = 50 cm (i + j) kN/C
(c) x = -25 cm, y = 75 cm ( i + j) kN/C
A 68 µC point charge is at the origin. Find the electric field at the following points. (a) x = 45 cm, y = 0 i MN/C
(b) x = 50 cm, y = 50 cm (i + j) kN/C
(c) x = -25 cm, y = 75 cm ( i + j) kN/C
A 68 µC point charge is at the origin. Find the electric field at the following points. (a) x = 45 cm, y = 0 i MN/C
(b) x = 50 cm, y = 50 cm (i + j) kN/C
(c) x = -25 cm, y = 75 cm ( i + j) kN/C

Explanation / Answer

A) E = k*q/x^2 = (9*10^9*68*10^-6)/(0.45*0.45) = 3.022*10^6 N/C = 3.022i MN/C

B) E = Ex+Ey

Ex = k*q/x^2 = (9*10^9*68*10^-6)/(0.5*0.5) = 2448*10^3 i N/C

Ey = (9*10^9*68*10^-6)/(0.5*0.5) = 2448*10^3 j N/C

then E = 2448*(i+j) kN/C

C) Ex= (-9*10^9*68*10^-6)/(0.25*0.25) = -9792*10^3 i N/C

Ey= (9*10^9*68*10^-6)/(0.75*0.75) = 1088*10^3 j N/C

then E = -9792*10^3 i N/C + 1088*10^3 j N/C

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