003 (part 1 of 2) 10.0 points Assume that you have two objects, one with a mass

Question

003 (part 1 of 2) 10.0 points Assume that you have two objects, one with a mass of 5 kg and the other with a mass of 15 kg, each with a charge of 0.03 C and separated by a distance of 8 m. What is the electric force that these objects exert on one another? Answer in units of N.
004 (part 2 of 2) 10.0 points What is the gravitational force between them? Answer in units of N.
005 10.0 points A charge of 8 µC is on the y axis at 3 cm, and a second charge of 8 µC is on the y axis at 3 cm.

Find the force on a charge of 6 µC on the x axis at x = 3 cm. The value of the Coulomb constant is 8.98755 × 109 N · m2/C2. Answer in units of N.
006 (part 1 of 2) 10.0 points A 2.2 µC point charge is on the x-axis at 4.6 m, and a 4.5 µC point charge is on the x-axis at 2.8 m. Find the magnitude of the net electric eld at the point on the y-axis where y = 2.2 m. The value of the Coulomb constant is 8.98755 × 109 N · m2/C2. Answer in units of N/C.
007 (part 2 of 2) 10.0 points Determine the direction of this electric eld (as an angle between 180 and 180 measured from the positive x-axis, with counterclockwise positive.) Answer in units of .
008 10.0 points The electron gun in a television tube is used to accelerate electrons with mass 9.109 × 1031 kg from rest to 2 × 107 m/s within a distance of 5 cm. What electric eld is required? The fundamental charge is 1.602 × 1019 C. Answer in units of N/C.
009 (part 1 of 3) 10.0 points An electron traveling at 1 × 106 m/s enters a 0.07 m region with a uniform electric eld of 51 N/C, as in the gure.
aul (a4676) – HW-2 Chapter-21 Electrostatics – erickson – (65704) 2
0.07 m
+++++++++ ˆ
ˆ
1 × 106 m/s
Find the magnitude of the acceleration of the electron while in the electric eld. The mass of an electron is 9.109 × 1031 kg and the fundamental charge is 1.602 × 1019 C. Answer in units of m/s2.
010 (part 2 of 3) 10.0 points Find the time it takes the electron to travel through the region of the electric eld, assuming it doesn’t hit the side walls. Answer in units of s.
011 (part 3 of 3) 10.0 points What is the magnitude of the vertical displacement y of the electron while it is in the electric eld? Answer in units of m.
012 (part 1 of 2) 10.0 points
Two point charges, 2.6 pC and 2.6 pC, are separated by 4 µm. What is the dipole moment of this pair of charges? Answer in units of C · m.
013 (part 2 of 2) 10.0 points Sketch the pair of charges, including the direction of the dipole moment.
1.
q +q ~p
2.
q +q ~p
3.
q +q ~p
4.
q +q ~p
014 10.0 points Two identical small charged spheres hang in equilibrium with equal masses as shown in the gure. The length of the strings are equal and the angle (shown in the gure) with the vertical is identical.
0.15 m
3 0.03 kg 0.03 kg Find the magnitude of the charge on each sphere. The acceleration of gravity is 9.8 m/s2 and the value of Coulomb’s constant is 8.98755 × 109 N · m2/C2 . Answer in units of C.
015 10.0 points A rod 6.4 cm long is uniformly charged and has a total charge of 29.9 µC. Find the magnitude of the electric eld along the axis of the rod at a point 52.3821 cm from the center of the rod. The Coulomb constant is 8.98755 × 109 N · m2/C2. Answer in units of N/C.
016 10.0 points A circular arc has a uniform linear charge density of 4 nC/m.
266
2.4 m
x
y
aul (a4676) – HW-2 Chapter-21 Electrostatics – erickson – (65704) 3
What is the magnitude of the electric eld at the center of the circle along which the arc lies? The value of the Coulomb constant is 8.98755 × 109 N · m2/C2. Answer in units of N/C.
017 (part 1 of 4) 10.0 points Consider a disk of radius 3.9 cm with a uniformly distributed charge of +4.7 µC. Compute the magnitude of the electric eld at a point on the axis and 3.1 mm from the center. The value of the Coulomb constant is 8.98774 × 109 N · m2/C2 . Answer in units of N/C.
018 (part 2 of 4) 10.0 points Compute the eld from the near-eld approximation x R. Answer in units of N/C.
019 (part 3 of 4) 10.0 points Compute the electric eld at a point on the axis and 31 cm from the center of the disk. Answer in units of N/C.
020 (part 4 of 4) 10.0 points Approximate the eld by treating the disk as a +4.7 µC point charge at a distance of 31 cm. Answer in units of N/C.

Explanation / Answer

given,

mass of first object = 5 kg

mass of second object = 15 kg

charge of both object = -0.03 C

distance between them = 8m

force between two charged particle = k * q1 * q2 / d^2

force between two charged particle = 9 * 10^9 * -0.03 * -0.03 / 8^2

electric force between two charged particle = 126562.5 N

gravitational force between two particles = G * m1 * m2 / d^2

gravitational force between two particles = 6.67384 * 10-11 * 5 * 15 / 8^2

gravitational force between two particles = 7.821 * 10^-11 N

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