PLEASE HELP!!!! Exercise 9.23 A flywheel with a radius of 0.300 m starts from re

Question

PLEASE HELP!!!!

Exercise 9.23

A flywheel with a radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.500 rad/s2 .

Part A

Compute the magnitude of the tangential acceleration of a point on its rim at the start.

0.150

SubmitMy AnswersGive Up

Correct

Part B

Compute the magnitude of the radial acceleration of a point on its rim at the start.

0

SubmitMy AnswersGive Up

Correct

Part C

Compute the magnitude of the resultant acceleration of a point on its rim at the start.

0.150

SubmitMy AnswersGive Up

Answer Requested

Part D

Compute the magnitude of the tangential acceleration of a point on its rim after it has turned through 60.0 .

0.150

SubmitMy AnswersGive Up

Correct

Part E

Compute the magnitude of the radial acceleration of a point on its rim after it has turned through 60.0 .

1.022

SubmitMy AnswersGive Up

Incorrect; Try Again; 3 attempts remaining

Part F

This question will be shown after you complete previous question(s).

Part G

Compute the magnitude of the tangential acceleration of a point on its rim after it has turned through 120.0 .

SubmitMy AnswersGive Up

Part H

Compute the magnitude of the radial acceleration of a point on its rim after it has turned through 120.0 .

SubmitMy AnswersGive Up

Part I

This question will be shown after

Exercise 9.23

A flywheel with a radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.500 rad/s2 .

Part A

Compute the magnitude of the tangential acceleration of a point on its rim at the start.

atan =

0.150

  m/s2  

SubmitMy AnswersGive Up

Correct

Part B

Compute the magnitude of the radial acceleration of a point on its rim at the start.

arad =

0

  m/s2  

SubmitMy AnswersGive Up

Correct

Part C

Compute the magnitude of the resultant acceleration of a point on its rim at the start.

a =

0.150

  m/s2  

SubmitMy AnswersGive Up

Answer Requested

Part D

Compute the magnitude of the tangential acceleration of a point on its rim after it has turned through 60.0 .

atan =

0.150

  m/s2  

SubmitMy AnswersGive Up

Correct

Part E

Compute the magnitude of the radial acceleration of a point on its rim after it has turned through 60.0 .

arad =

1.022

  m/s2  

SubmitMy AnswersGive Up

Incorrect; Try Again; 3 attempts remaining

Part F

This question will be shown after you complete previous question(s).

Part G

Compute the magnitude of the tangential acceleration of a point on its rim after it has turned through 120.0 .

atan =   m/s2  

SubmitMy AnswersGive Up

Part H

Compute the magnitude of the radial acceleration of a point on its rim after it has turned through 120.0 .

arad =   m/s2  

SubmitMy AnswersGive Up

Part I

This question will be shown after

Explanation / Answer

here,

radius of the wheel , r = 0.3 m

angular accelration , alpha = 0.5 rad/s^2

the magnitude of the tangential acceleration of a point on its rim at the start,at = r * alpha

at = 0.5 * 0.3

at = 0.15 m/s^2

the magnitude of the tangential acceleration of a point on its rim at the start is 0.15 m/s^2

part B)

the radial accelration , ar = w^2*r

as the rim is at rest at start,w=0

therefore, ar = 0

the magnitude of the radial acceleration of a point on its rim at the start is 0

part c)

the magnitude of the resultant acceleration of a point on its rim at the start, a = sqrt(ar^2 + at^2)

a = 0.15 m/s^2

the magnitude of the resultant acceleration of a point on its rim at the start is 0.15 m/s^2

part d)

the magnitude of the tangential acceleration of a pointon its rim after it has turned through 60.0 degree ,at = r * alpha

at = 0.5 * 0.3

at = 0.15 m/s^2

the magnitude of the tangential acceleration of a point on its rim after it has turned through 60.0 degree is 0.15 m/s^2

part e)

when theta = 60 degree

theta = 1.046 rad

initial angular velocity , w0 = 0

let the final velocity be w

using third equation of motion

w^2 - w0^2 = 2 * alpha * theta

w^2 = 2 * 1.046 * 0.5

w = 1.02 rad/s

radial accelration , ar' = w^2 * r

ar' = 1.02^2 * 0.3

ar = 0.314 m/s^2

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.