PLASE answer for PART A,and B (Figure 1) A satellite of mass m is in a circular
ID: 1403566 • Letter: P
Question
PLASE answer for PART A,and B
(Figure 1) A satellite of mass m is in a circular orbit of radius R2 around a spherical planet of radius R1 made of a material with density p. ( R2 is measured from the center of the planet, not its surface.) Use G for the universal gravitational constant. Part A Find the kinetic energy of this satellite, K. Part B Find U, the gravitational potential energy of the satellite. Take the gravitational potential energy to be zero for an object infinitely far away from the planet.Explanation / Answer
A)
Kinetic Energy of Satellite is given by = GMm / 2R
Where M is mass of Planet
m is mass of Satellite
G is Gravitational Constant
R is Radius of Circular orbit of Satellite = R2
Now Density = Mass / Volume
Mass of Planet (M) = Density () * 4/3 * PI * R13
Substituting Value of M in above equation -
K.E = G * () * 4/3 * PI * R13 * m / 2R2
K.E = (2GR13 m) /3R2
B)
Potential Energy of a satellite in a circular orbit is given as -
P.E = -GMm / r
Substituting Value of M and Solving similarly Potential Energy comes out to be -
P.E = - (4GR13 m ) /3R2
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.