-Monochromatic light falling on two slits 0.0375 mm apart produces the sixth-ord

Question

-Monochromatic light falling on two slits 0.0375 mm apart produces the sixth-order fringe at a 5.31° angle. What is the wavelength of the light used?

-In a double-slit experiment it is found that blue light of wavelength 471 nm gives a second-order maximum at a certain location on the screen. What wavelength of visible light would have a minimum at the same location?

-White light containing wavelengths from 403 nm to 757 nm falls on a grating with 7130 lines/cm. How wide is the first-order spectrum on a screen 2.39 m away?

Explanation / Answer

Here ,

slit distance , d = 0.0375 mm

for m = 6

theta = 5.31 degree

as the bright fringe position is given as

d*sin(theta) = m*wavelength

0.0375 *10^-3 * sin(5.31) = 6 * wavelength

wavelength = 5.784 *10^-8 m

the wavelength of the light used is 5.784 *10^-8 m

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please post the other questions in a seperate posts

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