1.)An 21-turn circular coil of radius 19.7 cm carries a current of 2.49 A. What
ID: 1402134 • Letter: 1
Question
1.)An 21-turn circular coil of radius 19.7 cm carries a current of 2.49 A. What is the strength of the magnetic field at a point on the coil's axis that is 41.1 cm from the center of the coil?
2.)A current of 7.03 A in a solenoid of length 10.8 cm creates a 0.313-T magnetic field at the center of the solenoid. How many turns does this solenoid contain?
3.)A doubly ionized molecule (i.e., a molecule lacking two electrons), moving in a magnetic field, experiences a magnetic force of 5.53 × 10-16 N as it moves at 309 m/s at 79.5° to the direction of the field. Find the magnitude of the magnetic field.
Explanation / Answer
1) on the axis of the loop,
B = (N*mue*I*r^2)/(2*(x^2 + r^2)^(3/2) )
= (21*4*pi*10^-7*2.49*0.197^2)/(2*(0.411^2 + 0.197^2)^1.5 )
= 1.35*10^-5 T
2) Apply, B = mue*N*I/L
==> N = B*L/(mue*I)
= 0.313*0.108/(4*pi*10^-7*7.03)
= 3827
3) Apply, F = q*v*B*sin(79.5)
==> B = F/(q*v*sin(79.5))
= 5.53*10^-16/(2*1.6*10^-19*309*sin(79.5))
= 5.68 T
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