A dime is placed in front of s concave mirror that has a radius of curvature 0.4

Question

A dime is placed in front of s concave mirror that has a radius of curvature 0.45m the image of the dime is inverts and three times the size of be time determine the distance between the dime and the mirror A dime is placed in front of s concave mirror that has a radius of curvature 0.45m the image of the dime is inverts and three times the size of be time determine the distance between the dime and the mirror A dime is placed in front of s concave mirror that has a radius of curvature 0.45m the image of the dime is inverts and three times the size of be time determine the distance between the dime and the mirror

Explanation / Answer

Magnification

M=-di/do =3

di=-3do

Focal length

f=R/2 =0.45/2 =0.225 m

From thin lens formula

1/f =1/di + 1/do

1/0.225 =1/-3do +1/do

do=0.15 m

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