The figure shows the cross-section of a very long solenoid (shown in dark). The

Question

The figure shows the cross-section of a very long solenoid (shown in dark). The current through the solenoid changes with time. Two conducting loops are placed in a plane perpendicular to the long axis of the solenoid, and are co-axial with the solenoid. How do the electromotive forces induced in the loops compare?

?1 > ?2

?1 ? ?2

?2 > ?1

There are no e.m.f's induced, since the loops are outside the solenoid.

?1 > ?2

?1 ? ?2

?2 > ?1

There are no e.m.f's induced, since the loops are outside the solenoid.

Explanation / Answer

Here ,

as the magnetic field due to solenoid is only inside the solenoid.

Now, emf induced = rate of change of flux

emf induced = Area of inner solenoid * dB/dt

Now, as the area of inner loop and dB/dt is same for both the loops

Hence , the induced emf is same for both the loops.

Hence , E1 = E2

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