Help with 9 and 10 uhD maximum height of the ball above the horizontal surface?

Question

Help with 9 and 10 uhD maximum height of the ball above the horizontal surface? 9. A 25 kg rocket starts on a launch pad at rest when its engines rocket upward with a constant 500 N thrust force. The engi abruptly cut off. The maximum height of the rocket is 35 m. How much energy doe fire and a constant thrust pushes nes fire for the first 20 m and then the take away from the rocket? s air resistance 10. The terminal velocity of an object is the speed an object must fall at to have a constant velocity, when the air resistance force balances out the gravitational force. The terminal velocity of a particular 5.0 kg ball is 25 m/s. If this ball is falling downward at 25 m/s, it falls with constant velocity. How much energy does the ball lose to air resistance for every meter that it falls? How t14: Conservation of Energy 6

Explanation / Answer

Note that

Wncon = Wthrust + Wfriction = delta KE + delta PE

At the peak, KEf = 0 as well, and KEi = 0 at launch.

The final PEf = m g (35 m). Thus,

Wthrust + Wfriction = m g (35 m) = 8575 J

As Wthrust = F d = (500 N)(20 m) = 10000 J

Thus,

10000 J + Wfriction = 8575 J

Wfriction = 1425 J [ANSWER]

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