resistance of box B i. Is the resistance of box A greater than. less than, or eq
ID: 1400045 • Letter: R
Question
resistance of box B i. Is the resistance of box A greater than. less than, or equal to the Explain. Less-than· Since the tulb2 rs neo ii. Has the current through battery 1 changed? If so, how? Yes, ance there is wore poroer aud wore Cuerent, so the aut hrough datlory chang ii. Has the current through battery 2 changed? If so, how? Ko, Siuce the civeuit is sesies so the urrent will be )o, giace the circui t ister ' eg go the current usill 3. The bulbs in the circuit at right are identical and the battery is ideal. a. Consider the circuit as shown. i. Rank bulbs A, B, and C in order of brightness. determined your answer Explain how you ACcause he ourrant ll frt pass nn alb A slile after asins talb A the ourt ant is divtd ut o cause the currant oi psts alb A So at A, there is More ourentthrepore A is the bria So AA A , there is more arrest ,t iii. Write an equation that relates the voltage across bulbs A and B to the battery voltage. iv. Is the voltage across bulb A greater than, less than, or equal to one half the battery voltage? Explain your reasoning. ials in Introductory Physics rmott, Shaffer, and the P.E.G., U. Wash Custom 2d Ed., for U.CO.Explanation / Answer
ii) think of bulbs AS resistances, now resistances A , B and c all are equal.
but A has higher current and b and c gets equal current flowing through them, as V = IR
so Va = Ia R Vb = Ib R and Vc = Ic R
as Ib and Ic are equal so Vb = Vc but Ia =2Ib = 2Ic
so Va = 2 Vb = 2Vc
Va>Vb=Vc
iii) let Vs be the battery voltage
writing the KVL
Vs = Va +Vb
iv)
Vs = Va +Vb = Va + Va/2 = 3/2 *Va = 1.5 Va
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.