1)In the figure below, the work done by the electrostatic force as the test char

Question

1)In the figure below, the work done by the electrostatic force as the test charge (q0 = 2 ?C) moves from A to B is WAB = 5x10-5 J. Find (a) the difference in the electric potential energies of the charge between these points and (b) the potential difference ?V between the points.(2)

2)The capacitance of an empty capacitor is 1.2 ?F. The capacitor is connected to a 12 V battery and charged up. It is then connected to a second capacitor of capacitance C. The final voltage of both capacitors is 6 V. What was the capacitance C? (2)

3)A spark plug in a car engine consists of two metal conductors that are separated by a distance of 0.75 mm. When an electric spark jumps between them, the magnitude of the electric field is 4.7x107 V/m. What is the magnitude of the potential difference ?V between the conductors? (1)

Explanation / Answer

these are 3 different question.As per guideliness,I can only answer one for you

3)

V=Ed

where v is potential difference

and d is distance

so V= 4.7x10^7*(0.75*10^-3)

V=3.525*10^4

V=35250V--answer

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.