The next twelve questions are about this circuit. The voltage of the battery is

Question

The next twelve questions are about this circuit. The voltage of the battery is 12 V, and the values of the resistances are: R1 = 5 ohms, R2 = 10 ohms, R3 = 15 ohms, and R4 = 20 ohms.

1)  R1 and R3 are in:

parallel

series

neither

2)  R2 and R4 are in:

parallel

series

neither

3)  Compare the magnitude of the current through R2 and R3

I2 > I3

I2 = I3

I2 < I3

4)  Compare the magnitude of the voltage across R1 and R3

V1 > V3

V1 = V3

V1 < V3

5)  Compare the magnitude of the voltage across R2 and R4

V2 > V4

V2 = V4

V2 < V4

6)  Compare the magnitude of the current through R1 and R4

I1 > I4

I1 = I4

I1 < I4

7)  Calculate the total equivalent resistance of this circuit.

2.11 ohms

4.06 ohms

8.73 ohms

24.9 ohms

50.0 ohms

8)  Calculate the current going through R1.

0.34 A

0.57 A

1.58 A

2.40 A

2.74 A

9)  Calculate the current going through R2.

0.37 A

0.57 A

1.58 A

2.40 A

2.74 A

10)  Calculate the voltage drop across R3.

3.4 V

5.7 V

8.3 V

10.2 V

12 V

11)  Calculate the voltage drop across R4.

3.7 V

5.7 V

8.6 V

10.2 V

12 V

12)  Calculate the total power dissipated in this circuit.

12 W

24 W

35 W

48 W

60 W

Explanation / Answer

R2 and R4 are in parallel and their parallel combination is given as ::

R24 = R2 R4/(R2 + R4)

R24 = 10 (20)/(10 + 20)

R24 = 6.67 ohm

R3 and R24 are in series and their series combination is given as ::

R234 = R3 + R24 = 15 + 6.67 = 21.67 ohm

R234 and R1 are in parallel and their parallel combination is given as ::

R1234 = R234 x R1 / (R234 + R1)

R1234 = 21.67 (5) / (21.67 + 5)

R1234 = 4.06 ohm

total Power dissipated is given as ::

P = V2 /R1234 = 122 /4.06 = 35 Watt

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