A dockworker applies a constant horizontal force of 87.0 N to a block of ice on

Question

A dockworker applies a constant horizontal force of 87.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves a distance 11.5m in a time of 4.50 s. For general problem-solving tips and strategies for this topic. you may want to view a Video Tutor Solution of Determining force from acceleration. Part A What is the mass of the block of ice? Part B If the worker stops pushing after 4.50s , how far does the block move in the next 5.20 s?

Explanation / Answer

From the acceleration we get the final speed:

vf = v_0 +at = (87/76.6)(4.5)=5.11 m/s

the distance in 5.20 s we have:

d = vf

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