Two identical weights are attached at the end of a string as shown. The tension

Question

Two identical weights are attached at the end of a string as shown. The tension in the string as measured by the weightless spring scale is

A 2W
B W
C 0.5W
D W^2
E sq. root 2W

1. Two identical weights are attached at the end of a string as shown. The tension in the string as measured by the weightless spring scale is A. 2W B. W C. 0.5 W D. w E. V2 W 2. 80 N weight is supported by two weightless wires A and B as shown. The tension in each wire (in N) is: A TA-0 and T 80 B. TA-40 and Ta40 C. TA-40 /cos (6) and Ts 40/cos (0) D. TA-40 . cos (9) and Ta = 40 . cos (9) E. Ta = 40 /sin (9) and T = 40 /sin (9) 3. A block of mass m 2.0 kg is launched with a speed of 8.0 m/s on a floor that has a coefficient of kinetic friction of 0.25. The maximum distance the block goes A. 2 m B. 2.5 m C. 5 m D. 8 m E. 12.75 m

Explanation / Answer

a)

The Tensions in both the threads = W

So, the spring scale will measure = 2*W <------ as there are two tensions from both sides

2)

2*T*sinQ = Mg = 80 <-------- Q = angle theta

So, T = 40/sinQ on both the string <------- options E

3)

Work done by friction = initial Kinetic energy

So, umg*x = 0.5*mv^2

where x =distance covered

So, x = 0.5*v^2/ug = 0.5*8^2/(0.25*9.8) = 12.8 m <-------answer

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