a golfer hits a ball with an initial speed of 30 m/s at an angle of 40 degrees t

Question

a golfer hits a ball with an initial speed of 30 m/s at an angle of 40 degrees to the horizontal. if the ball is in the air for 6 seconds which of the following expressions will be equal to the horizontal distance traveled by the ball?
A. (15)(6)^2(cos40)m
B. (30)(6)(cos40)m

C. (15)(6)^2(sin40)m

D. (30)(6)^2(sin40)m
a golfer hits a ball with an initial speed of 30 m/s at an angle of 40 degrees to the horizontal. if the ball is in the air for 6 seconds which of the following expressions will be equal to the horizontal distance traveled by the ball?
A. (15)(6)^2(cos40)m
B. (30)(6)(cos40)m

C. (15)(6)^2(sin40)m

D. (30)(6)^2(sin40)m
a golfer hits a ball with an initial speed of 30 m/s at an angle of 40 degrees to the horizontal. if the ball is in the air for 6 seconds which of the following expressions will be equal to the horizontal distance traveled by the ball?
A. (15)(6)^2(cos40)m
B. (30)(6)(cos40)m

C. (15)(6)^2(sin40)m

D. (30)(6)^2(sin40)m

Explanation / Answer

B. (30)(6)(cos40)m

here is the explanation

vox = vo*cos(theta) = 30*cos(40)

time taken, t = 6 s

horizonatl distance travelled, x = vox*t = 30*cos(40)*6 m

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