a force of 39.0 N is required to start a 3.0 kg box moving across a horizontal c

Question

a force of 39.0 N is required to start a 3.0 kg box moving across a horizontal concrete floor.
A. Hat is the coefficient of static friction between the box and the floor?
B. If the 39.0 N force continues, the box accelerates at 0.54 m/s^2. What is the coefficient of kinetic friction? a force of 39.0 N is required to start a 3.0 kg box moving across a horizontal concrete floor.
A. Hat is the coefficient of static friction between the box and the floor?
B. If the 39.0 N force continues, the box accelerates at 0.54 m/s^2. What is the coefficient of kinetic friction? a force of 39.0 N is required to start a 3.0 kg box moving across a horizontal concrete floor.
A. Hat is the coefficient of static friction between the box and the floor?
B. If the 39.0 N force continues, the box accelerates at 0.54 m/s^2. What is the coefficient of kinetic friction?

Explanation / Answer

a)
use:
applied force is equal to force of static friction
Hat*m*g = F
Hat*3*9.8 = 39
Hat=1.33
Answer: 1.33

b)
Once box starts moving, kinetic frictiuon aacts on it
F-f= m*a
39 - miu*m*g = m*0.54
39 - miu*3*9.8 = 3*0.54
miu=1.27
Answer: 1.27

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