fhgc Part Il Proplems Doy of s. Ted pohts each. Show n\'t forget unit 1. charges

Question

fhgc Part Il Proplems Doy of s. Ted pohts each. Show n't forget unit 1. charges of 6 microcoulombs and 10 micloco ulombs are 10 cm. arart Calculate their force of repulsion. Calculate the electric field midway etween them. 2. e charges i#1 catulate the potential midway between them. Calculate the work to bring an electron from far away to midway between them. An AC circuit has a source of 12 volts and 500 hz. It is connected in series with 50 ohms, 10 microfarads and 2 millihenries. Find the current and power in the 3. circuit. Fill in the table below Device Hair dryer TV Vacuum Car starter12 alculator V volts 120 120 120 I amps R ohms P watts 1000 15 20 6 0.03 For the circuit to the right calculate total resistance, total current, and current and voltage for each resistor. For the circuit to the right write down enough equations using Kirchhoff's rules to solve the circuit. For extra credit: sqlve them A long straight wire carries a curreht of Stamos. hat is th strength 10 cm ic field the wire? Wot would be the folce on an electon moving m(s naal to the wire?

Explanation / Answer

3)

Xc = 1/2*pi*f*C = 1/(2*3.14*500*10*10^-6) = 31.85

XL = 2*pi*f*L = 2*3.14*500*2*10^-3 = 6.28

R = 50

Z = sqrt(R^2 + (Xc-XL)^2)

Z = sqrt(50^2+(31.85-6.28)^2) = 51.2 ohms

current = Io = Eo/Z = 12/51.2 = 0.234A   <--------answer

power P = Eo*Io*R/2Z

P = (12*0.234*50)/(2*51.2) = 1.37 watts <--------answer
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4)

power = P = V*I = I*R^2 = V^2/R

V = I*R

hair dryer   120        8.33      14.04       1000

TV           120          2          60       240

vacuum        120         8           15       960

Car starter   12         20          0.6       240

calculator     6         0.005        1200     0.03

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5)

10 & 15 are in parallel R1 = (10*15)/(10+15) = 6

Rtot = 6 + 6 = 12 ohms

Itot = E/Rtot = 12/12 = 1 A

current through 6 ohms = Itot = 1 A

current through 10 ohms = 1*(15/25) = 0.6 A

current through 15 ohms = 1 - 0.6 = 0.4 A

potential through 6 ohms = 1*6 = 6 v

potential through 10 ohms = 12-6 = 6 v

potential through 15 ohms = 12 - 6 = 6 v

+++++++++++++++++++++

6)

R1 = 8

R2 = 9

R3 = 10

I1 = I2 + I3

for left loop

e - I1*R1 - I2*R2 = 0

e - I2*R1 - I3*R1 - I2R2 = 0

for right loop

I2*R2 - I3*R3 = 0

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