Scattering cross section of each particle is 5.0 x 10^-12 m^-2 Absorption cross

ID: 1392300 • Letter: S

Question

Scattering cross section of each particle is 5.0 x 10^-12 m^-2

Absorption cross section is .4x10^-2 m^-2

Concentration of particles is the layer is N=5*10^7m^-3

Assume layer is illuminatred by electromagnetic radiation incident at an angle 30 degrees from the vertical. Assume layer is 1.5 km thick

a) Calculate transmittance of each layer

b) What fraction of energy not transmitted through the layeer is lost to absorption?

c) What fraction of energy not transmitted through the layer is lost to scattering?

PART-A:-
A= a*b*c where, a= 4x10^-2 m^-2 b= 1.5*10^3m c= 5*10^7m^-3
& A= absorption.
Now, Transmittance,T= 1/e^A

PART-B:-
fraction of energy not transmitted through the layeer which is lost to absorption is:- (A-T)/A

PART-C:-

fraction of energy not transmitted through the layeer which is lost to scattering is:-

From bragg's equation, we know that, 2d*sin(theta)= n*lambda where, d= 1.5*10^3m & lambda= scattering cofficient.

Find Lambda.

So, fraction of energy not transmitted through the layeer which is lost to scattering= e^(-lambda*d)-1

Put the value and get the result.

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