A mirror positioned 10.0 cm to the right of an object forms an image (also to th

Question

A mirror positioned 10.0 cm to the right of an object forms an image (also to the right of the object) with a magnification of +1.50. (a) Is the mirror concave or convex? (b) Where is the image located? (c) What is the focal length of the mirror? (d) Now suppose that the mirror is replaced by a lens, which is adjusted until an image of the same magnitude magnification as before is formed at the same location to the right of the object as before. Is it a converging or diverging lens? (e) Is it a real or virtual image? (f) How far away from the object is the lens located? (g) What is its focal length?

Explanation / Answer

a) Yes mirror will be the concave mirror

b) Image distance will be =q = ?

Image distance will be formed by the formula of the magnification

M = q / p

q = PM

q = 10cm(1.50) = 15cm

c) focal length = f = pq / (P + q)

f = 10cm(15cm) / 25cm

f =6cm

d) The lense will be the converging lense

e) Image will be real image

f) The object will be located at 10cm as in above mirror case

g) The focal length of the lense will be same to the mirror which is 6cm.

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