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a. current in wire b. strength of magnetic field c. not sure what its asking ple

ID: 1390410 • Letter: A

Question




a. current in wire
b. strength of magnetic field
c. not sure what its asking
please answer a b and c with work. thank you!!!!

A long straight wire is made from carbon (resistivity at room temperature - 3.50 Times 105 Ohm m). The wire is 15.0 m long and has a radius of 5.00 Times 104 m. There is a potential difference of 15.0 V between its ends. Find the current in the wire. Find the strength of the magnetic field at a point that is midway between the wire's ends and a distance of 2.00 Times 10 3 m from the central axis of the wire. Suppose that we wanted to produce this potential difference between the ends of the wire by moving it in a magnetic field with a strength of 2.00 T. Let the wire be perpendicular to the field; let the wire's velocity be perpendicular to the field too. How fast must the wire be moving?

Explanation / Answer

As

R = rho L / A

and

A = pi r^2 = 7.854E-7 m^2

Then

R = 668.45 ohm

Thus,

I = V / R = 0.0224 A or 22.4 mA [ANSWER]

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