A 48.0 kiloton atomic bomb releases as much energy as 48.0 kilotons of TNT (1.0

Question

A 48.0 kiloton atomic bomb releases as much energy as 48.0 kilotons of TNT (1.0 kiloton of TNT releases about 5.0 x 10^12) of energy). Recall that about 200 MeV of energy is released when each 92^U235 nucleus fissions. (a) How many 92U^235 nuclei are fissioned to produce the bombs energy? (b) How many grams of uranium are fissioned? (c) What is the equivalent mass (in grams) of the bomb?s energy? Take the Avogadro?s number to be 6.02 x 10^23 mole-1. (a) Number Units (b) Number Units (c) Number Units

Explanation / Answer

energy released by atomic bomb = E= 48*5e12 = 2.4e+14 J

1 ev = 1.6e-19 J

E = 2.4e+14/(1.6e-19) = 1.5e+33 eV = 1.5e27 Mev

part a)

energy of each uranium atom Eo= 200 Mev

total energy of N atoms = N*Eo

E = N*Eo

N = E/Eo = 1.5e27/200 = 7.5e+24 <-----answer

part b)

mass of avagadro number of atoms is 235 g

mass of N atoms = (235*N/NA)

m = (235*7.5e24)/6.02e23 = 2927.74 grams <---answer

part c)

E = mo*c^2

mo = E/c^2 = 1.5e27/(3e8*3e8) = 1.67e10 kg = 1.67*10^13 g

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.