007 (part 1 of 4) An object is placed 24.5 cm in front of a convex mirror of foc
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Question
007 (part 1 of 4)
An object is placed 24.5 cm in front of a convex mirror of focal length 50 cm.
Note:
Do convex mirrors have a positive or
negative focal length?
What is its image position?
Answer in units of cm.
008 (part 2 of 4) 10.0 points
The magnification of the image in the previ-
ous question is:
009 (part 3 of 4) 10.0 points
With the arrangement discussed above, the
image is:
1.
virtual, erect, smaller than object
2.
virtual, erect, bigger than object
3.
real, same size as object
4.
virtual, inverted, bigger than object
5.
real, erect, bigger than object
6.
real, erect, smaller than object
7.
virtual, same size as object
8.
real, inverted, bigger than object
9.
virtual, inverted, smaller than object
010 (part 4 of 4) 10.0 points
An object is placed at 66.3 cm in front of this
mirror.
What is its image position?
Answer in units of cm
Explanation / Answer
for convex mirror, its focal length is -ve
so apply for converging ( concave) lens 1/f = 1/u + 1/v
u = oject distance,
v= image distance
and f = focal length
magnifiication m = -(v/u)
Power P of a lens = 1/focal length in meter
Power P is measured in DIopters
apply for diverginh lens (convex lens) -1/f = 1/u + 1/v
u = oject distance, v= image distance and f = focal length
magnifiication m = -(v/u) =y'/y ) =y'/y
so
part A:
1/v = 1/f -1/u
v = uf/(u-f)
v = -24.5 * 50/(24.5 + 50)
v = 16.44 cm
--------------------------------------
magnification m = -(-16.44)/24.5
m = 0.671
-----------------------------------
6.
real, erect, smaller than object
---------------------
if u = 66.3 cm
v = uf/(u-f)
v = -66.3 * 50/(66.3 + 50)
v = -28.5 cm
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