A photoresistor, whose resistance decreases with light intensity, is connected i

Question

A photoresistor, whose resistance decreases with light intensity, is connected in the circuit of the figure. On a sunny day, the photoresistor has a resistance of0.52k? . On a cloudy day, the resistance rises to5.0k? . At night, the resistance is 22k?

A)

What does the voltmeter read on a sunny day?

B)

What does the voltmeter read on a cloudy day?

c)

What does the voltmeter read at night?

d)

Does the voltmeter reading increase or decrease as the light intensity increases?

The voltmeter reading decreases because the current through the resistor increases. The voltmeter reading increases because the current through the resistor decreases. The voltmeter reading decreases because the current through the resistor decreases. The voltmeter reading increases because the current through the resistor increases.

Explanation / Answer

The reading, as the resistors are in series, is

V = 9.0 V (1.0 kohm)/(1.0 kohm + R)

Thus,

A. V = 5.92 V

B. V = 1.50 V

C. V = 0.391 V

D. The voltmeter reading INCREASES because the current through the resistor INCREASES. [OPTION D]

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