A photo of a large bucket wheel reclaimer is shown in Figure 2. The reclaimer bu

Question

A photo of a large bucket wheel reclaimer is shown in Figure 2. The reclaimer bucket is driven via an induction motor through a gearbox as illustrated in Figure 3. The induction motor rotates at a speed of 840 rpm with a power of 1000 kW. The gearbox casing contains the input pinion and gear (Ip and Ig), gears A, B, C, D, E, F and the planetary gear train. The parameters of the gearbox are given in Table 1. The earner arm is bolted to the bucket wheel and the ring gear is fixed. Determine the speed ratio of the gearbox Determine the torque on the input and output shafts of the gearbox, m units of Nm assuming 100 % efficient gearing Calculate the speed of the bucket wheel m RPM. The earner arm holds the five planet gears m position as they mesh with the sun and nng gears The earner arm can be approximated as a steel cylinder with inner and outer diameters of 300 mm and 1 m respectively and thickness of 100 mm The steel planet gears have pitch diameter of 250 mm. face width of 200 mm and are mounted 0.5 m from the centre of rotation of the carrier arm Calculate the inertia of the planetary gear system (earner arm and planet gears) about the earner arm axis Each individual fixed axis gear mesh (IpIg, AB, CD and EF) is given as 99.5 % efficient while the planetary' gear system is given as being 99 % efficient Calculate the equivalent inertia of the rotating bucket wheel and gearbox components about the input shaft. Calculate the overall efficiency, the subsequent power available about the bucket wheel axis of rotation and the power loss in the gearbox

Explanation / Answer

1: Get the simple ratio 2: Use the torque formula 3: Use speed formula 4: Use the inertia formula 5: Use the equivalent inertia formula

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