The kinetic energy of a rolling billiard ball is given by KE=1/2 m v 2. Suppose

Question

The kinetic energy of a rolling billiard ball is given by KE=1/2mv2. Suppose a 0.17-kg billiard ball is rolling down a pool table with an initial speed of 4.5m/s . As it travels, it loses some of its energy as heat. The ball slows down to 3.7m/s and then collides straight-on with a second billiard ball of equal mass. The first billiard ball completely stops and the second one rolls away with a velocity of 3.7m/s . Assume the first billiard ball is the system

Calculate ?E for the process.

Express your answer using two significant figures.

Explanation / Answer

original KE

0.5*0.17*4.52= 1.7J

Final KE= 0J (it stopped)

?E= Final KE-original KE=-1.7J

point two KE
0.5*0.17*3.72=1.16 J

q= point two KE-original KE

(KE lost is equal to thermal energy as it's the only energy conversion in this problem)

w= ?E-q

q=1.16-1.7

=-0.54J

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