1) With the alpha particle energy set at 7.0 MeV, what Z will allow a closest ap
ID: 1378898 • Letter: 1
Question
1) With the alpha particle energy set at 7.0 MeV, what Z will allow a closest approach of 20.0 fm? (Since Z is quantized to integers, give the number that gives the nearest value.)
2) With the alpha particle energy set at 4.0 MeV, what value of Z results in a closest approach of 36.0 fm? (Since Z is quantized to integers, give the value that results in the best answer.)
3) With a Z of 48, what alpha particle energy (in MeV) results in a closest approach of 17.0 fm? (The available energies are to two significant figures, so give the best value.) Do not include units in your answers, just the number of MeV.
4) With a Z of 41, what alpha particle energy in MeV (given the available choices set to two places accuracy) gives a closest approach of 12.0 fm? Make sure and give the answer that comes closest to the desired distance.
Explanation / Answer
Sorry we are allowed to solve one question at a time.
So I am solving first one , but here rest will be solved by same approach.
Here kinetic energy will convert into potential energy
therfore
Initial energy is given as = 7*106 eV = 7*106 *1.6*10-19 = 1.12*10-12 J
Now potential energy =(2e*Ze) /(4Pieo*R) where R is distance ,
= 9*109*Z*2e2 /(20*10-15)
Potential = kinetic energy
Z = 48.69
so it will be 49
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