Exercise 30.4 A solenoidal coil with 24 turns of wire is wound tightly around an

Question

Exercise 30.4

A solenoidal coil with 24 turns of wire is wound tightly around another coil with 340 turns. The inner solenoid is 25.0cm long and has a diameter of 2.50cm . At a certain time, the current in the inner solenoid is 0.100A and is increasing at a rate of 1800A/s .

Part A

For this time, calculate the average magnetic flux through each turn of the inner solenoid.

SubmitMy AnswersGive Up

Part B

For this time, calculate the mutual inductance of the two solenoids;

SubmitMy AnswersGive Up

Part C

For this time, calculate the emf induced in the outer solenoid by the changing current in the inner solenoid.

SubmitMy AnswersGive Up

Exercise 30.4

A solenoidal coil with 24 turns of wire is wound tightly around another coil with 340 turns. The inner solenoid is 25.0cm long and has a diameter of 2.50cm . At a certain time, the current in the inner solenoid is 0.100A and is increasing at a rate of 1800A/s .

Part A

For this time, calculate the average magnetic flux through each turn of the inner solenoid.

?B = Wb

SubmitMy AnswersGive Up

Part B

For this time, calculate the mutual inductance of the two solenoids;

M = H

SubmitMy AnswersGive Up

Part C

For this time, calculate the emf induced in the outer solenoid by the changing current in the inner solenoid.

E2 = V

SubmitMy AnswersGive Up

Explanation / Answer

Part A)

Flux = BA and B = uNI/L

Flux = (4pi X 10-7)(340)(.1)(pi)(.0125)2/(.25)

Flux = 8.39 X 10-8 Wb

Part B)

M = uN1N2A/l1

M = (4pi X 10-7)(24)(340)pi(.0125)2/.25

M = 2.01 X 10-5 H

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.