Both question A and Question B refer to the figures posted with this assignment.
ID: 1376461 • Letter: B
Question
Both question A and Question B refer to the figures posted with this assignment. The figures show systems of standing waves set up in strings, fixed at both ends, under tension. All of the strings are identical, except for their lengths, and are under the same tension. The variables in these situations, in addition to the lengths of the strings, are amplitude A at the antinodes and the number of nodes.
A.Rank these systems, from greatest to least, on the basis of the frequencies of the waves. In addition, give a complete physics explanation for your ranking.
B.Rank these systems, from greatest to least, on the basis of the wavelengths of the waves. In addition, give a complete physics explanation for your ranking.
Both question A and Question B refer to the figures posted with this assignment. The figures show systems of standing waves set up in strings, fixed at both ends, under tension. All of the strings are identical, except for their lengths, and are under the same tension. The variables in these situations, in addition to the lengths of the strings, are amplitude A at the antinodes and the number of nodes. A.Rank these systems, from greatest to least, on the basis of the frequencies of the waves. In addition, give a complete physics explanation for your ranking. B.Rank these systems, from greatest to least, on the basis of the wavelengths of the waves. In addition, give a complete physics explanation for your ranking. (Please explain why you rank in this specific way. What related information is needed? Thank you.Explanation / Answer
frequency*wavelength=speed
as they are under the same tension and they have same mass per unit length,
speed is same throughout.
then frequency is inversely proportional to wavelength.
hence higher the wavelength, lower the freqeuncy.
A:5*lambda/2=25
lambda=10 cm
B: 7*lambda/2=28
lambda=8 cm
C:3*lambda/2=27
lambda=18 cm
D: 4*lambda/2=28
lambda=14 cm
E: 4*lambda/2=20 cm
lambda=10 cm
F: 3*lambda/2=30
lambda=20 cm
G: 5*lambda/2=50
lambda=20 cm
so frequency ranking:
B>A=E>D>C>F=G
wavelength ranking will be the opposite.
G=F>C>D>E=A>B
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