A 100-W light bulb is powered by 120 V rms ac 60.0-Hz household connection. Dete

Question

A 100-W light bulb is powered by 120 V rms ac 60.0-Hz household connection.

Determine: A) the rms current B) the current amplitude. (Show your work to recieve credit for your answer)

For Part A I believe I need to use the same basic formula for Power to find the current rms, which would be P=IrmsVrms. I don't think we need frequency in this equation.

This would be 100W = Irms120Vrms = Irms = 100W/120Vrms = Irms = 0.8333 A

Not sure if this is correct.

For Part B, current amplitude I believe is Max current represented as I0 in the equation Irms = I0/Square Root of 2

So, I0 = (0.8333 A)(Square Root of 2) = 1.178511297 A

Not sure if this is correct because the value looks high.

Explanation / Answer

power=rms voltage*rms current

rms current=100/120=0.8333 A

b)the current amplitude=rms current*sqrt(2)
=1.1785 A

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