My problem is the second question, how could I get the force, what\'s the ?C? My

Question

My problem is the second question, how could I get the force, what's the ?C?

My problem is the second question, how could I get the force, what's the ?C? ing the symmetry of the arrangement, determine the direction of the force on q in the figure below, given that qa=q0=+8.05 MuC, qc=-8.05 MuC, and q is positive. right down and left up and left left up down up and right down and right Calculate the magnitude of the force on the charge q, given that the square is 10.80 cm on a side and q=2.45 Mu C. Number N

Explanation / Answer

seperation between each charge and q is

r = sqrt ( ( 10.8 cm /2 ) ^2 + ( 10.8 cm /2 ) ^2 )

= 7.63 cm

The electric force due to each charge on q is

F= k q_a q / r ^2

= ( 9 *10^ 9 ) ( 8.05*10^ -6 C ) (2.45*10^ -6 C) / ( 7.63*10^ -2 m ) ^2

= 30.488 N

Since the charge are at same distance and smamagnitude. the upper two charge are positive and lower two are negative. so the horizontal component of net forces acts on the charge q is zero.

net force

F = sqrt [( 4 F sin ( 45 ) )^2 ]

= 9.286 N

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