A ball is launched as a projectile with initial speed u at an angle e above the

Question

A ball is launched as a projectile with initial speed u at an angle e above the horizontal. Using conservation of energy, find the maximum height hmax of the ball's flight. Express your answer in terms of u, g, and theta. Part H A ball is launched with initial speed u from ground level up a frictionless slope. The slope makes an angle theta with the horizontal. Using conservation of energy, find the maximum vertical height h, to which the ball will climb. Express your answer in terms of u, g, and S. You may or may not use all of these quantities. hmax = Part I A ball is launched with initial speed u from the ground level up a frictionless hill. The hill becomes steeper as the ball slides up: however, the ball remains m contact with the hill at all times. Using conservation of energy, find the maximum vertical height to which the ball will climb. Express your answer in terms of v and g.

Explanation / Answer

D) conserving energy

Initial kinetic energy = final potential energy

0.5 m v^2 = m g h

hmax= V2/2g ( answer )

E ) at V = 0.5 v

conserving energy

0.5mv^2 = 0.5 m (0.5v)^2 + mg h

h = 0.75 V2/2g

F ) at h = hmax/2

0.5mv^2 = 0.5mv12 + mg ( 0.5hmax)

V1 = v /sqrt (2)

G ) from conserving energy

at maximum height velocity of ball = Vx = u cos theta

therefore

0.5mV^2 = 0.5m Vx2 + mg Hmax

Hmax= u2sin2theta /2g

H) I) both the cases the result is same

conserving energy

0.5mv^2 = mgh

Hmax= V2/2g

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.