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PLEASE ANSWER QUESTIONS :) Problem 7.25. A charge of 1.7 x 10-’ C is moving nort

ID: 1372319 • Letter: P

Question

PLEASE ANSWER QUESTIONS :)

Problem 7.25. A charge of 1.7 x 10-’ C is moving north with a velocity of 3 x 105 What magnetic field (magnitude and direction) does it produce at a point due east which is 1.2 x 10-2 m away?

Ans. 0.35 T, vertically down

Problem 7.26. A charge of - 1.7 x 10-3 C is moving south with a velocity of 3 x 105 m/s. What magnetic field (magnitude and direction) does it produce at a point due west which is 1.2 x 10-2 m away?

Am. 0.35 T, vertically up

Problem 7.27. A charge of - 1.7 x 10-’ C is moving west a velocity of 3 x 105 m/s. What magnetic field (magnitude and direction) does it produce at a point, P, which is reached by going north 1.2 x 10-2 m and then west by 0.9 x 10-2 m? (See Fig. 7-28.)

Ans. 0.18 T, vertically up

Problem 7.28. An elevator, carrying a charge of 0.2 C, is moving down with a velocity of 4 x 103 m/s. The elevator is 10 m from the bottom and 3 m horizontally from point P in Fig. 7-29. What magnetic field does it produce at point P?

Ans. 2.1 x 1OP5 T, out

Explanation / Answer

magnetic field = k * q * (v x r) / r^2

magnetic field = k * q * (v * r * sin(90)) / r^2

magnetic field = k * q * (v * r ) / r^2

magnetic field = k * q * v / r

magnetic field = 10^-7 * 1.7 * 10^-3 * 3 * 10^5 / (1.2 * 10^-2)

magnetic field = 0.00425 T, vertically downward

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