You are on a train that is traveling at 3.0 m/s along a level straight track. Ve

Question

You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that slopes upward at a 12° angle with the horizontal. As you face the window ( 0.742 m high, 2.40 m wide) in your compartment, the train is moving to the left, as the drawing indicates. The top edge of the wall first appears at window corner A and eventually disappears at window corner B. How much time passes between appearance and disappearance of the upper edge of the wall?

Explanation / Answer

Given that

The speed of the train(v) =3.0m/s

The slope of the wall with track (theta) =12degreees

and also given that As you face the window ( 0.742 m high, 2.40 m wide) in your compartment

The distance d is equal to the length of the window + base of the 12 degrees traingle of height 0.742m

Now considering the triangle we get

b =0.742/tan12 =3.490m

Thus the distance d =2.40+3.490 =5.890m

Now the time required for the train to travel 5.890m is given by

time =distance/velocity =5.890m/3m/s =1.963s

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