I calculated like M= miuo*N1*N1*A*L = (1.26*10^-6)*1000*300*(10^-4)*(0.08) =3.02

Question

I calculated like

M= miuo*N1*N1*A*L
= (1.26*10^-6)*1000*300*(10^-4)*(0.08)
=3.024*10^-6 H

but it is wrong..

kakaotalk teringPhysics. A x /a Home | Chegg.com x MasteringPhysics: Chap 30 (deadline: 10:00 pm, Saturday, 10/31/15) - Google Chrome www.chegg.com/homework-help/questions-and-answers/inductor-hooked-ac-voltage-source-voltage-E https://session.masteringphysics.com/myct/itemView?assignmentProblemlD 513914958 offset-prev MENU> An inductor is hooked up to an AC voltage source. The voltage source l x PHY 132 Classical Physics Il Fall 2015 Signed in as HyungBin Kim Help Close ± Mutual Inductance of a Tesla Coil Resources tudyIquestions and answers/science / physics/an inductor is hooked up to an ac voltage source 2of18 | next Post new question stion Mutual Inductance of a Tesla Coil Part A A long solenoid (black coil) with cross-sectional area A = 1.00 cm2 and length L = 8.00 cm is wound with n1 = 1000 turns of wire. (Figure 1) A time-varying current 21 = 8.000 A flows through this wire. A shorter coil (blue coil) with n2 = 300 turns of wire surrounds it. Use 140- Find the value M of the mutual inductance ctor is hooked up to an AC voltage source. The voltage source has EMF VO and frequency f. The current de in the inductor is 10 Physics tutors who can help rig now s the inductance L of the inductor? s your answer in terms of V0, f, and 10 Note: The current in black coil is constantly changing. However, when using the hints it may help you to consider the instant at which the current in the black coil is i1 8.000 A Yoav K. Washington Univers... Express your answer symbolically using the terms given in the question or numerically (in henry) if given numerical values 1.26x10-6 m ould happen to the amplitude of the current in the inductor if the inductance L were doubled? vould be no change in the amplitude of the current plitude of the current would be doubled. plitude of the current would be halved plitude of the current would be quadrupled. Johns Hopkins Univ… Kevin S University at Buffalo omments (2)> M0.004725 Answer See more tutors Submit Hints My Answers Give Up Review Part Fi Anonymous answered this 2 minutes later 385 answers Was this answer helpful? Incorrect, Try Again, 3 attempts remaining Continue View comments(1) Area A Blue coil: n, turns Black coil: n, turns ABOUT CHEGG Media Center RESOURCES Mobile Publishers Join Our Affiliate Program Advertising Choices TEXTBOOK LINKS Return Your Books Rent Textbooks eTextbooks Used Textbooks Cheap Textbooks College Textbooks STUDENT SERVICES Chegg Study Help Chegg Coupon Solutions Manual Scholarships Career Search Online Tutoring COMPANY Chegg College Blog Jobs Customer Service Give Us Feedback or Brand Partnerships Policy Your CA Privacy Rights riv nput interpretation 1.26 x 10-6 x 1000 . 300%- erms se 2015-10-31

Explanation / Answer

magnetic field produced by solenoid.

B = mue*N1*I/L

magnetic flux through second coil = N2*A*B

= N2*A*mue*Ni*I/L

we know magnetic flux through the second coil = M*I

N2*A*mue*Ni*I/L = M*I

==> M = mue*N1*N2*A/L

= 1.26*10^-6*1000*3000*10^-4/0.8

= 4.725*10^-4 H <<<<<--------Answer

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