Most gasoline engines in today\\\'s automobiles are belt driven. This means that

Question

Most gasoline engines in today's automobiles are belt driven. This means that the crankshaft, a rod which rotates and drives the pistons, is timed to the camshaft, the mechanism which actuates the valves, by means of a belt. Starting from rest, assume it takes t = 0.0980 s for a crankshaft with a radius of r1 = 5.25 cm to reach 1750 rpm. If the belt doesn't stretch or slip, calculate the angular acceleration, 2, of the larger camshaft, which has a radius of r2 = 10.5 cm, during this time period.

Explanation / Answer

here ,

for the smaller shaft ,

as alpha1 = (wf - wi)/t

alpha1 = (1750 * 2 pi/60)/0.0980

alpha1 = 1869.6 rad/s^2

Now , as the tangential acceleration of both cranks will be same

alpha1 * r1 = alpha2 * r2

1869.6 * 5.25 = alpha2 * 10.5

alpha2 = 934.8 rad/s^2

the angular acceleration of larger crank is 934.8 rad/s^2

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.