A 1.10-kg wrench is acting on a nut trying to turn it. the length of the wrench

Question

A 1.10-kg wrench is acting on a nut trying to turn it. the length of the wrench lies directly to the east of the nut. A force 150.0 N acts on the wrench at the position 15.0 cm from the center of the nut in a direction 30.0 degree north of east. what is the magnitude of the torque about the center of the nut ?

In my calculator, it gives me -22.3, or 22.3 for magnitude, but both on my study guide and other online answers, others claim it to be 11.25, or half.

What am I doing wrong? I've tried 3 different calculators!

Explanation / Answer

Your equation is absolutely correct

torque = force *Sin theta * distance

T = (150)(Sin30)(0.15)

T = 11.25 N-m

Please use calculator in degree

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