A 1.05 kg block is placed against a rough wall and is held stationary by a force
ID: 1904166 • Letter: A
Question
A 1.05 kg block is placed against a rough wall and is held stationary by a force of 8.6 N applied at a 45 degree angle as shown in the drawing. What is the magnitude of the friction force?
I thought I knew how to do it, but when I entered my answer, it said my response was incorrect. If you could, please provide a detailed solution, with some explanation, that way I can understand it for next time.
A 1.05 kg block is placed against a rough wall and is held stationary by a force of 8.6 N applied at a 45 degree angle as shown in the drawing. What is the magnitude of the friction force? I thought I knew how to do it, but when I entered my answer, it said my response was incorrect. If you could, please provide a detailed solution, with some explanation, that way I can understand it for next time.Explanation / Answer
Friction=uN N=FCOS(45) Friction=uN=uxFCOS(45) now for vertical direction mg=uFsin(45) u=mg/Fsin(45) Friction=FCOS(45)mg/Fsin(45) =cot(45)mg=mg=10.29 N
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