A force of 33.0 N is directed downward perpendicular to the stick at Point J. Wh

Question

A force of 33.0 N is directed downward perpendicular to the stick at Point J. What is the torque from this force?

A force of 10.0 N is directed upward perpendicular to the stick at Point G. What is the torque from this force?

A force of 40.0 N is directed upward at angle 37.0° to the right of the perpendicular to the stick at Point A. What is the torque from this force?

A force of 33.0 N is applying horizontally to the left at A. What is the torque from this force?

Two forces are applied simultaneously to the stick. A force of 13.0 N is directed upward perpendicular to the stick at Point J and a force of 10.0 N is directed upward perpendicular to the stick at Point G. What is the net torque from these two forces?

Explanation / Answer

1.

F = 13 N up

r = distance from axis of rotation L = d = 8 cm = 0.08 m

Torque = F r Sin90 = 13 x 0.08 = - 1.04 N-m     clockwise

2.

F = 33 N down

r = distance from axis of rotation L = d = 8 cm = 0.08 m

Torque = F r Sin90 = 33 x 0.08 = 2.64 N-m     counter-clockwise

3.

F = 10 N up

r = distance from axis of rotation L = 5d = 5 x 8 cm = 0.40 m

Torque = F r Sin90 = 10 x 0.40 = 4 N-m    counter- clockwise

4.

F = 40 N up

r = distance from axis of rotation L = 2d = 2 x 8 cm = 0.16 m

Torque = F r Sin(90-37) = 40 x 0.16 Sin = 5.11 N-m    counter clockwise

5.

F = 33 N up

r = distance from axis of rotation L = 2 d = 2 x 8 cm = 0.16 m

Torque = F r Sin00 = 33 x 0.08 x 0 = 0

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