A. Determine the vertical impulse required for a 57 kg high jumper to clear a he

Question

A. Determine the vertical impulse required for a 57 kg high jumper to clear a height of 6 ft 5 in. Assume that the high jumper's center of mass starts at 3 ft 5 in and that his center of mass just clears the bar. (positive up)
(include units with answer) B. A golfer playing on a level course hits a 48.7 g golf ball that leaves the tee at a 21° upward angle and hits the ground 164 m away. What was the magnitude of the impulse given to the ball? (neglect air resistance)
(include units with answer)

Explanation / Answer

Here ,

initial height , hi = 3 ft 5 in = 0.7366 m

final height , hf = 6 feet 5 in = 1.956 m

Now , height difference , h = hf - hi

h = 1.956 - 0.7366

h = 1.22 m

Now , intial velocity of jumper , v = sqrt(2 * g * h)

v = sqrt(2 * 9.8 * 1.22)

v = 4.89 m/s

impulse = change in momentum

impulse = 4.89 * 57

impulse = 278.7 Kg.m/s

the impulse from the ground is 278.7 Kg.m/s

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