A square loop consists of a single turn with a resistance of 6.00 . The loop has

Question

A square loop consists of a single turn with a resistance of 6.00 . The loop has an area of 600 cm2, and has a uniform magnetic field passing through it that is directed out of the page. The loop contains a 12-volt battery, connected as shown in the figure below.

A) At the instant shown in the figure, there is no net current in the loop. At what rate is the magnitude of the magnetic field changing?

B) If the polarity of the battery was reversed, and the magnetic field was still changing at the rate you calculated above, what would the magnitude of the net current through the loop be?

Explanation / Answer

e = -dphi/dt

here A is not changing and B and A are parallel to each other

dphi = d(BAcostheta) = AdB

e = -AdB/dt

dB/dt = -e/A

A = 600 cm^2 = 0.06 m^2

e = 12

dB/dt = -12/0.06 = - 200 T/s

part b )

If the polarity of the battery is reversed, the emf from the battery will now add to the emf from the magnetic field, so the total emf would now be 12 V + 12 V = 24 V.

I = V/R

I = 24/6 = 4 A

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