I Have solved 12, I just need solutions from 13 to 15 12[E]) You want to constru
ID: 1361182 • Letter: I
Question
I Have solved 12, I just need solutions from 13 to 15
12[E]) You want to construct a simple particle accelerator and hit on the following design: you will take two oppositely charged plates with small holes drilled into them and set them up parallel to each other. You will create a vacuum between the two plates and fire a beam of electrons through the small hole in the negatively charged plate, aimed so that the beam will emerge through the hole in the positively charged plate. You want the electrons in the beam to gain 6.0 eV of energy, so you need to work out what magnitude of voltage difference to set up between the two plates.
Correct, computer gets: 6.0E+00 V
Hint: Recall that an electron-Volt (eV) is the energy needed to move an electron through a 1 Volt voltage difference
13[M]) Your electron beam consists of electrons that are initially moving at around 2.1×105 m/s. You want to work out how fast the electrons are moving after passing through your accelerator.
14[E]) You decide to investigate the physical details of your electron accelerator a bit more closely. You start by determining the strength of the electric field between the plates. You've set the plates up so that their separation is 3 m.
15[M]) The plates you chose had areas of 5 mm^2. You want to know how much electrical energy is stored by the electric field between the plates.
Explanation / Answer
14) electric field =potential difference/seperation distance
E= 6/3*10^-6=2*10^6 VOLT/METER
15) CDAPACITANCE=A*8.85*10^-15/3*10^-6
C=5*10^-6*8.85*10^-12/3*10^-6=14.75*10^-12 F
ENERGY=1/2 CV^2=0.5*14.75*10^-12*36265.5*10^-12 J
13) 1/2Mv^2=QV
v=sqrt(2QV/M)=SQRT(2.109*10^15)=4.59*10^7 m/sec
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