Determine the center of mass of the carbon monoxide molecule, ^12C^16O, relative

Question

Determine the center of mass of the carbon monoxide molecule, ^12C^16O, relative to the location of the carbon atom. Carbon has 12 mass units and oxygen has 16 mass units. The equilibrium distance between the atoms is 112.8 pm. A horizontal beam has one end against a wall. The other end is supported by a cable that runs from the wall down to beam making an angle of 37 degrees with the beam. (Similar to figure P7.44 in your text.) The beam is uniform and has a mass of 21.0 kg. A flower pot of mass 32.0 kg hangs from the cable end of the beam. Make a drawing of the items in the problem and show all forces acting on the beam. Determine the tension in the cable and the force components at the wall.

Explanation / Answer

the location of center of mass is

X _cm = m1 x1 + m2 x2/ m1 + m2

= m_c x1 + m_0 x2/ m_c + m_o

= m_c (0) + m_0 ( 112.8 * 10 ^-12 m)/0.750 m_0 + m_0

=64.45 * 10 ^-12 m

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.